Hi , quick question is there a way on lakefs python api , to direct get_objects to output file into a specific dir instead of root temp dir configured on the client object?

Hi @Yaphet Kebede! Thanks for reaching out. Yes, you can write the output of the python API to any file and directory path you want to. What do you mean by

root temp dir configured on the client object

? Would you mind sharing how you configured that?

Hi @Vino , thanks for your quick response, sure,

def init_client(lakefs_conf_path):
    logger.debug('initializing ')
    configuration = lakefs_client.Configuration()
    configuration.temp_folder_path = os.path.join(os.path.dirname(os.path.abspath(__file__)), 'data')
    with open(lakefs_conf_path) as stream:
        config_raw = yaml.load(stream, Loader=yaml.FullLoader)

    configuration.username = config_raw["credentials"]["access_key_id"]
    configuration.password = config_raw["credentials"]["secret_access_key"]
    configuration.host = config_raw["server"]["endpoint_url"]
    the_lake = LakeFsWrapper(configuration=configuration)
    return the_lake

here's my client init, i set

configuration.temp_folder_path = os.path.join(os.path.dirname(os.path.abspath(__file__)), 'data')

as the correct path which is great, I can see the files being downloaded there when i make a call like

# path is lakefs location 
self._client.objects.get_object(repository=repository, ref=branch, path=location)

but what i wanted to do was say i have

some-path/some.txt

on lake fs , and wanted to download it to a local

<temp_folder_path>/some-path/some.txt

the

client.objects.get_objects

wouldn't let me as it would just dump

some.txt

directly under

<temp_folder_path>

, ignoring

some-path

Right, this makes sense. Let me look into this and get back to you in a bit!